"super db -c" no longer prints SUP on terminal by default

[philrz]

Note the ?foo? bar? output as the telltale sign of binary output rather than SUP.

$ super -version &&
  super db -db mydb init &&
  super db -db mydb create -use foo &&
  echo '{foo: "bar"}' |
  super db -db mydb load - && echo '{foo: "bar"}' | super db -db mydb -c "from foo" && rm -rf mydb

Version: v0.3.0-303-ge5ef10535

database created: file:///Users/phil/work/newbug/mydb
pool created: foo 3IvEhJHpSncKJNY355qlnMwGz3n
Switched to branch "main" on pool "foo"
(11/1) 13B 13B/s
3IvEhKSttpHBt5EhAZEOiGCJGXI committed

?foo? bar?

Details

Repro is with super commit e5ef105.

It seems like the problem surfaced with the merge of the changes in #7181, which fixed a different problem with default output format with super db (#7075), as the same repro steps produced SUP output at commit 44e0a65 just prior to the merge of #7181.

$ super -version &&
  super db -db mydb init &&
  super db -db mydb create -use foo &&
  echo '{foo: "bar"}' |
  super db -db mydb load - && echo '{foo: "bar"}' | super db -db mydb -c "from foo" && rm -rf mydb

Version: v0.3.0-302-g44e0a655a

database created: file:///Users/phil/work/newbug/mydb
pool created: foo 3IvFCI8ARivvRX9OHaK5Eoe6CAO
Switched to branch "main" on pool "foo"
(11/1) 13B 13B/s
3IvFCD7aES46CvDYYTTyTqJyXEM committed

{foo:"bar"}