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Semantics of no_deps hint on inner loops is not clear #554

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@roastduck

Suppose we mark no_deps in the j loop inside another i loop, like

for i in range(m):
  #! no_deps: a
  for j in range(n):
    a[f(i, j)]

Does it mean for all $\forall i, j_1, j_2, f(i, j_1) \ne f(i, j_2)$, or $\forall i_1, i_2, j_1, j_2, f(i_1, j_1) \ne f(i_2, j_2)$? The current code implements the latter, but I think users may want the former in most of the cases. We need to make it clear.

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