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2 changes: 1 addition & 1 deletion content/intuitionistic-logic/tableaux/soundness.tex
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Expand Up @@ -19,7 +19,7 @@
has a closed !!{tableau} then $!B_1, \dots, !B_n \Entails !A$. It is
easier to prove the contrapositive: if for some $\mModel{M}$ and
world~$w$, $\mSat{M}{!B_i}[w]$ for all $i=1$, \dots,~$n$ but
$\mSat{M}{!A}[w]$, then no !!{tableau} can close. Such a
$\mSat/{M}{!A}[w]$, then no !!{tableau} can close. Such a
countermodel shows that the initial assumptions of the !!{tableau}
are satisfiable. The strategy of the proof is to show that whenever
all the prefixed !!{formula}s on !!a{tableau} branch are
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Expand Up @@ -81,7 +81,7 @@
case~\olref{prop:ccs-closed}.}{}

\item If $\lnot!A \in \Gamma$, then by consistency $!A \notin
\Gamma$; and if $!A \notin \Gamma$ then $!A \in \Gamma$ since
\Gamma$; and if $!A \notin \Gamma$ then $\lnot !A \in \Gamma$ since
$\Gamma$ is complete $\Sigma$-consistent.

\tagitem{prvAnd}{\iftag{probAnd}{Exercise.}{Suppose $!A \land !B \in
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2 changes: 1 addition & 1 deletion content/normal-modal-logic/tableaux/soundness.tex
Original file line number Diff line number Diff line change
Expand Up @@ -28,7 +28,7 @@
has a closed !!{tableau} then $!B_1, \dots, !B_n \Entails !A$. It is
easier to prove the contrapositive: if for some $\mModel{M}$ and
world~$w$, $\mSat{M}{!B_i}[w]$ for all $i=1$, \dots,~$n$ but
$\mSat{M}{!A}[w]$, then no !!{tableau} can close. Such a
$\mSat/{M}{!A}[w]$, then no !!{tableau} can close. Such a
countermodel shows that the initial assumptions of the !!{tableau}
are satisfiable. The strategy of the proof is to show that whenever
all the prefixed !!{formula}s on !!a{tableau} branch are
Expand Down